A system uses a page size of 4 KB and a logical address space of 32 bits. How many bits are required for the page number?
Options
- A. 10 bits
- B. 12 bits
- C. 20 bits
- D. More than one of the above
- E. None of the above
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Quiz Practice:
Correct Answer (Detailed Explanation is Below)
C. 20 bits
Detailed Explanation
Explanation: Page size = 4 KB = 212 bytes, so the page offset requires 12 bits. The logical address is 32 bits. Therefore, page number bits = 32 − 12 = 20 bits.