What is the value of p in the following C++ code snippet?

int p;
bool a=true;
bool b=false;
int x=10;
int y=5;
p=((x|y)+(a+b));
cout<<p;

Options

B. 16

Answer: (A) 12

First calculate the bitwise OR operation:

x = 10 and y = 5.

In binary:

10 = 1010
5 = 0101

Therefore:

10 | 5 = 1111 = 15

Now, a = true has the integer value 1 and b = false has the integer value 0.

Therefore:

a + b = 1 + 0 = 1

Finally:

p = 15 + 1 = 16

Therefore, the correct answer is actually (B) 16. In C++, true converts to 1 and false converts to 0 during arithmetic.

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