Quiz Practice:
#include <iostream.h>
using namespace std;
void square(int *x, int *y)
{
*x = (*x) * --(*y);
}
int main()
{
int number = 30;
square(&number, &number);
cout << number;
return 0;
}
E. None of the above
Answer: (E) None of the above
The function receives the address of the same variable through both x and y.
Therefore, both *x and *y refer to the same object, number.
The expression (*x) * --(*y) both reads and modifies the same object without the required sequencing between those operations. This results in undefined behavior.
Undefined behavior does not guarantee a particular output such as 30 or 870, and it is also not specifically guaranteed to produce a segmentation fault.
Therefore, among the given choices, (E) None of the above is the best answer.